在使用JSON.NET序列化对象时，希望能够对一些属性字段的格式自定义处理，经常遇到的便是日期格式的自定义，下面就给出例子。
如有一个Person类，实例化Person对象时，希望BirthDate的格式结果为“yyyy/MM//dd”或“yyyy-MM-dd”:
class Person{ ???public string Name { get; set; } ???public int Age { get; set; } ???public DateTime BirthDate { get; set; }}1
class Person
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{3
public string Name { get; set; }4
public int Age { get; set; }5
public DateTime BirthDate { get; set; }6
}
第一种方法：
给JsonConvert.SerializeObject的方法传入自定义的格式化参数：
static void Main(string[] args){ ???var me = new Person ???{ ???????Name = "Medit Ding", ???????Age = 27, ???????BirthDate = DateTime.Parse("1992-11-13") ???}; ???var json1 = JsonConvert.SerializeObject(me); ???var json2 = JsonConvert.SerializeObject(me, new IsoDateTimeConverter { DateTimeFormat = "yyyy/MM/dd" }); ???Console.WriteLine($"json1:\t{json1}\r\njson2:\t{json2}"); ???Console.ReadKey();}1
static void Main(string[] args)
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{3
var me = new Person
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?{5
Name = "Medit Ding",
6
Age = 27,
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BirthDate = DateTime.Parse("1992-11-13")8
?};
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var json1 = JsonConvert.SerializeObject(me);
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var json2 = JsonConvert.SerializeObject(me, new IsoDateTimeConverter { DateTimeFormat = "yyyy/MM/dd" });12
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Console.WriteLine($"json1:\t{json1}\r\njson2:\t{json2}");14
Console.ReadKey();
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}
可以得到目标结果：
第二种方法：
给目标属性添加自定义格式化特性：
class Person{ ???public string Name { get; set; } ???public int Age { get; set; } ???[JsonConverter(typeof(DateTimeConverter),"yyyy/MM/dd")] ???public DateTime BirthDate { get; set; }}class DateTimeConverter : IsoDateTimeConverter{ ???public DateTimeConverter() ???????:base() ???{ ???????//Default datetime format ???????DateTimeFormat = "yyyy-MM-dd HH:mm:ss"; ???} ???public DateTimeConverter(string format) ???????:base() ???{ ???????DateTimeFormat = format; ???}}....static void Main(string[] args){ ???var me = new Person ???{ ???????Name = "Medit Ding", ???????Age = 27, ???????BirthDate = DateTime.Parse("1992-11-13") ???}; ???????var json = JsonConvert.SerializeObject(me); ???Console.WriteLine($"json:\t{json}"); ???Console.ReadKey();}1
class Person
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{3
public string Name { get; set; }4
public int Age { get; set; }5
6
?[JsonConverter(typeof(DateTimeConverter),"yyyy/MM/dd")]
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public DateTime BirthDate { get; set; }8
}
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class DateTimeConverter : IsoDateTimeConverter
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{12
public DateTimeConverter()
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?:base()
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?{15
//Default datetime format
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DateTimeFormat = "yyyy-MM-dd HH:mm:ss";
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?}
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public DateTimeConverter(string format)
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?:base()
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?{22
DateTimeFormat = format;
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?}
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}
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....
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static void Main(string[] args)
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{29
var me = new Person
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?{31
Name = "Medit Ding",
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Age = 27,
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BirthDate = DateTime.Parse("1992-11-13")34
?};
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var json = JsonConvert.SerializeObject(me);
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Console.WriteLine($"json:\t{json}");39
Console.ReadKey();
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}