主键生成策略使用UUID报出如警告如下：
控制台- 2017-11-24 18:40:14 [restartedMain] WARN ?org.hibernate.id.UUIDHexGenerator - HHH000409: Using org.hibernate.id.UUIDHexGenerator which does not generate IETF RFC 4122 compliant UUID values; consider using org.hibernate.id.UUIDGenerator instead
说是它不生成符合IETF RFC 4122标准的UUID值; 请考虑使用org.hibernate.id.UUIDGenerator。
实体如下：
package com.sxd.entity;import org.hibernate.annotations.GenericGenerator;import javax.persistence.*;@Entity@GenericGenerator(name = "jpa-uuid", strategy = "uuid")public class User { ???private String id; ???private String username; ???private String password; ???private Integer age; ???@Id ???@GeneratedValue(generator = "jpa-uuid") ???public String getId() { ???????return id; ???} ???public void setId(String id) { ???????this.id = id; ???} ???@Column(nullable = false) ???public String getUsername() { ???????return username; ???} ???public void setUsername(String username) { ???????this.username = username; ???} ???@Column(nullable = false) ???public String getPassword() { ???????return password; ???} ???public void setPassword(String password) { ???????this.password = password; ???} ???@Column(nullable = false) ???public Integer getAge() { ???????return age; ???} ???public void setAge(Integer age) { ???????this.age = age; ???} ???public User() { ???} ???public User(String id, String username, String password, Integer age) { ???????this.id = id; ???????this.username = username; ???????this.password = password; ???????this.age = age; ???}}有这个警告之后，处理如下：
package com.sxd.entity;import org.hibernate.annotations.GenericGenerator;import javax.persistence.*;@Entity@GenericGenerator(name = "uuid2", strategy = "org.hibernate.id.UUIDGenerator" )public class User { ???private String id; ???private String username; ???private String password; ???private Integer age; ???@Id ???@GeneratedValue(generator = "uuid2") ???public String getId() { ???????return id; ???} ???public void setId(String id) { ???????this.id = id; ???} ???@Column(nullable = false) ???public String getUsername() { ???????return username; ???} ???public void setUsername(String username) { ???????this.username = username; ???} ???@Column(nullable = false) ???public String getPassword() { ???????return password; ???} ???public void setPassword(String password) { ???????this.password = password; ???} ???@Column(nullable = false) ???public Integer getAge() { ???????return age; ???} ???public void setAge(Integer age) { ???????this.age = age; ???} ???public User() { ???} ???public User(String id, String username, String password, Integer age) { ???????this.id = id; ???????this.username = username; ???????this.password = password; ???????this.age = age; ???}}即可解决这个警告。
【hibernate】主键生成策略使用UUID报出如下警告：org.hibernate.id.UUIDHexGenerator - HHH000409: Using org.hibernate.id.UUIDHexGenerator which does not generate IETF RFC 4122 compliant UUID values;
原文地址：http://www.cnblogs.com/sxdcgaq8080/p/7891954.html