skynet.timeout 传进去 number 范围内的数值但是会溢出,
调查发现 skynet.timeout 调用的是 c 的方法：
c.intcommand("TIMEOUT",ti)对应的C方法中会把传入的 number 转换成 int32:
static intlintcommand(lua_State *L) { ???struct skynet_context * context = lua_touserdata(L, lua_upvalueindex(1)); ???const char * cmd = luaL_checkstring(L,1); ???const char * result; ???const char * parm = NULL; ???char tmp[64]; ??// for integer parm ???if (lua_gettop(L) == 2) { ???????if (lua_isnumber(L, 2)) { ???????????int32_t n = (int32_t)luaL_checkinteger(L,2); ???????????sprintf(tmp, "%d", n); ???????????parm = tmp; ???????} else { ???????????parm = luaL_checkstring(L,2); ???????} ???} ???result = skynet_command(context, cmd, parm); ???if (result) { ???????char *endptr = NULL; ????????lua_Integer r = strtoll(result, &endptr, 0); ???????if (endptr == NULL || *endptr != '\0') { ???????????// may be real number ???????????double n = strtod(result, &endptr); ???????????if (endptr == NULL || *endptr != '\0') { ???????????????return luaL_error(L, "Invalid result %s", result); ???????????} else { ???????????????lua_pushnumber(L, n); ???????????} ???????} else { ???????????lua_pushinteger(L, r); ???????} ???????return 1; ???} ???return 0;}所以传入数字不再 2^31 ~ -2^31 的值都将会溢出，然后就导致bug产生。
skynet的timer似乎有问题
原文地址：https://www.cnblogs.com/adoontheway/p/9974528.html