1.如果转换的是Map、或者是简单的对象
package com.gc.action;import java.util.Map;import net.sf.json.JSONObject;/** * 1.json string 转换为 map * 2.json string 转换为 对象 * @author zhangtengda * */public class JsonUtils { ???public static void main(String[] args) { ???????String jsonStr = "{\"status\":\"0\",\"data\":{\"name\":\"tom\",\"age\":18}}"; ???????// ================================ ???????// 1.如果是拿出来最外层的 map ???????Map<Object, Object> result = jsonToMap(jsonStr); ???????System.out.println(result.get("status")); ???????System.out.println(result.get("data")); ???????// 2.如果进步一拿到内层的 map ???????Map<Object, Object> data = jsonToMap(result.get("data")); ???????System.out.println(data.get("name")); ???????System.out.println(data.get("age")); ???????// ================================ ???????Long beginTime = System.currentTimeMillis(); ???????// 3.转换为对象 ???????String personStr = "{\"id\":12,\"name\":\"mary\"}"; ???????Person person = jsonToBean(personStr, Person.class); ???????System.out.println(person); ???????System.out.println("耗时：" ?+( System.currentTimeMillis() - beginTime)); ???} ???/** ????* json string 转换为 map 对象 ????* @param jsonObj ????* @return ????*/ ???public static Map<Object, Object> jsonToMap(Object jsonObj) { ???????JSONObject jsonObject = JSONObject.fromObject(jsonObj); ???????Map<Object, Object> map = (Map)jsonObject; ???????return map; ???} ???/**json string 转换为 对象 ????* @param jsonObj ????* @param type ????* @return ????*/ ???public ?static <T> ?T jsonToBean(Object jsonObj, Class<T> type) { ???????JSONObject jsonObject = JSONObject.fromObject(jsonObj); ???????T obj =(T)JSONObject.toBean(jsonObject, type); ???????return obj; ???} }json转换成Map
原文地址：https://www.cnblogs.com/zhao-shan/p/9045367.html