本文实例讲述了ASP.NET利用第三方类库Newtonsoft.Json
提取多层嵌套json数据的方法,具体例子如下。
假设需要提取的json字符串如下:
{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}
先引用命名空间:
using Newtonsoft.Json;using Newtonsoft.Json.Linq;
可以把上面的json字符串看成一个对象,只要编写对应的类即可(如果使用VS2013进行开发,可以通过“编辑--选择性粘贴--将JSON粘贴为类”快速地将json字符串转换为实体类)
???public class UserInfo ???{ ???????public string name; ???????public int age; ???????public address addr; ???} ???public class address ???{ ???????public string city; ???????public string province; ???}
1、将json字符串转换为实体对象的代码如下:
string jsonData="{\"name\":\"lily\",\"age\":23,\"addr\":{\"city\":guangzhou,\"province\":guangdong}}";UserInfo user=(UserInfo)JsonConvert.DeserializeObject(jsonData, typeof(UserInfo));
2、读取json中某个属性的值可以使用一下代码:
JObject jsonObj = JObject.Parse(jsonData);string name=jsonObj ["name"].ToString();string age=jsonObj ["age"].ToString();string city=((JObject )jsonObj ["addr"])["city"].ToString();string province=((JObject )jsonObj ["addr"])["province"].ToString();
3、解释多层嵌套json,获取任意属性的值:
如果需要处理的json字符串如下:
{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}};
然后让你输入一个对象,如“city”,系统就会输出“guangzhou”,输入“age”,就输出“23”。由于json是多级嵌套的,所以需要逐个遍历,代码如下:
???????public string GetJsonValue(JEnumerable<JToken> jToken, string key) ???????{ ???????????IEnumerator enumerator = jToken.GetEnumerator(); ???????????while (enumerator.MoveNext()) ???????????{ ???????????????JToken jc = (JToken)enumerator.Current; ???????????????if (jc is JObject || ((JProperty)jc).Value is JObject) ???????????????{ ???????????????????return GetJsonValue(jc.Children(), key); ???????????????} ???????????????else ???????????????{ ???????????????????if (((JProperty)jc).Name == key) ???????????????????{ ???????????????????????return ((JProperty)jc).Value.ToString(); ???????????????????} ???????????????} ???????????} ???????????return null; ???????}
调用GetJsonValue的代码:
string jsonData = "{\"name\":\"lily\",\"age\":23,\"addr\":{\"city\":\"guangzhou\",\"province\":\"guangdong\"}}";JObject jsonObj = JObject.Parse(jsonData);Response.Write(GetJsonValue(jsonObj.Children(), "province"));
如果是多层嵌套的数组,也可以使用以下代码:
string jsonData = "{\"addr\":[{\"city\":\"guangzhou\",\"province\":\"guangdong\"},{\"city\":\"guiyang\",\"province\":\"guizhou\"}]}";JObject jsonObj = JObject.Parse(jsonData);JArray jar = JArray.Parse(jsonObj["addr"].ToString());JObject j = JObject.Parse(jar[0].ToString());Response.Write(j["city"]);
4、JSON转XML:
string xmlstr=((XmlDocument)JsonConvert.DeserializeXmlNode(jsonData)).InnerXml.ToString();