路由系统分发的本质
反向生成redirect跳转url
1.在urls.py中指定url的name
from django.conf.urls import urlfrom django.contrib import adminfrom app01 import viewsurlpatterns = [ ???url(r'^index/', views.index, name="INDEX"), ???url(r'^login/', views.login),]
2.在views视图函数中使用reverse指定 INDEX地址
from django.shortcuts import render, HttpResponse, redirectfrom django.shortcuts import reversedef index(request): ???return HttpResponse("hello")def login(request): ???# 通过reverse("INDEX") 指向 "INDEX" 别名 ???return redirect(reverse("INDEX"))
应用url的分发include
1.将包含cmdb应用的url请求,转发给cmdb引用中的urls.py中
from django.conf.urls import url, includefrom django.contrib import adminfrom app01 import viewsurlpatterns = [ ???# 127.0.0.1:8000/cmdb/xxxx/ ??cmdb的url 转到cmdb 应用下的urls中 ???url(r'^cmdb/', include("cmdb.urls")),]
2.在指定APP的项目中,创建一个 urls.py文件
from django.conf.urls import urlfrom cmdb import viewsurlpatterns = [ ???# 跳转到该应用中的 views 视图函数中 ???url(r'^hosts/$', views.hosts),]
反向生成URL地址,指定namespace
1.将指定app的url跳转,加上namespace="o",指定跳转到哪个应用app
from django.conf.urls import url, includefrom django.contrib import adminfrom app01 import viewsurlpatterns = [ ???# url(r'^admin/', admin.site.urls), ???url(r'^index/', views.index, name="INDEX"), ???url(r'^login/', views.login), ???url(r'^cmdb/', include("cmdb.urls", namespace="c")), ???url(r'^openstack/', include("openstack.urls", namespace="o")),]
2.在views的视图函数中,使用redirect跳转路径时需要加上前缀"o:hosts"
from django.shortcuts import render, HttpResponse, redirectfrom django.shortcuts import reversedef index(request): ???return HttpResponse("hello")def login(request): ???# 登录成功后,跳转到 openstack 应用的 主机列表页面 ???return redirect(reverse("o:hosts"))
通过 循环的形式 添加URL地址
from django.conf.urls import urlfrom app01 import viewsurlpatterns = [ ???# url(r'^admin/', admin.site.urls), ???# url(r'^index/', views.index, name="INDEX"), ???url(r'^login/', views.login),]# 通过for 循环将,生成的url 添加到 urlpatterns 中for i in range(10): ???temp = [] ???for j in range(5): ???????temp.append(url(r'^inner_%s/' % j, views.login)) ???v = url(r'^login_%s/' % i, (temp, None, None)) ???urlpatterns.append(v)
输出,生成的url列表:
^login/^login_0/ ^inner_0/^login_0/ ^inner_1/^login_0/ ^inner_2/^login_0/ ^inner_3/^login_0/ ^inner_4/^login_1/^login_2/^login_3/^login_4/^login_5/^login_6/^login_7/^login_8/^login_9/