Ajax API
var reqUrl = "http://192.168.31.162:8081/obtain/onlineState?name=aa01&password=010203";var postUrl = "http://192.168.31.162:8081/update/remoteClientInfo";/** * 页面 * ???http://192.168.31.162:8081/http/ajax/Aj01-HttpRequest.html * ajax get 请求 * ?http://www.w3school.com.cn/ajax/ajax_xmlhttprequest_send.asp */function testAjaxGet() { ???debugger; ???var xmlhttp; ???if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari ???????xmlhttp = new XMLHttpRequest(); ???} ???else {// code for IE6, IE5 ???????xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); ???} ???xmlhttp.open("GET", reqUrl, true);// ???????xmlhttp.open("GET", reqUrl, false); ???xmlhttp.send();// ???????console.log(xmlhttp.responseText); ???xmlhttp.onreadystatechange = function () { ?// 异步方法回调 ???????if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { ???????????console.log(xmlhttp.responseText); ???????} ???}}/** * Ref: * */function testAjaxPost() { ???debugger; ???var xmlhttp; ???if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari ???????xmlhttp = new XMLHttpRequest(); ???} ???else {// code for IE6, IE5 ???????xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); ???} ???xmlhttp.open("POST", postUrl, true);// ???????xmlhttp.open("POST", postUrl, false); ???xmlhttp.setRequestHeader("Content-type","application/json"); ???var jsonObj = { ???????name:"AAA" ???}; ???xmlhttp.send(JSON.stringify(jsonObj));// ???????console.log(xmlhttp.responseText); ???xmlhttp.onreadystatechange = function () { ?// 异步方法回调 ???????if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { ???????????console.log(xmlhttp.responseText); ???????} ???}}参考：
AJAX - 向服务器发送请求 w3c
js ajax请求
原文地址：http://www.cnblogs.com/zhen-android/p/7643382.html