package com.montnets.emp.sysuser.biz;import org.apache.axis.client.Call;import org.apache.axis.client.Service;import javax.xml.namespace.QName;import javax.xml.rpc.encoding.XMLType;/** * @Description TODO * @Author lensener * Date 2019/3/25 0025 上午 9:14 */public class TestWebService { ???public static void main(String[] args) throws Exception { ???????String url = "http://*:*/MWGate/wmgw.asmx";// 提供接口的地址 ???????String soapaction = "http://tempuri.org/"; // 域名，这是在server定义的--不知道的可以问接口提供方，他们一并提供这个 ???????String userId = "TEST06"; ???????String password = "123456"; ???????Service service = new Service(); ???????try{ ???????????Call call = (Call) service.createCall(); ???????????call.setTargetEndpointAddress(url); ???????????call.setOperationName(new QName(soapaction, "hello")); // 设置要调用哪个方法 ???????????call.addParameter(new QName(soapaction, "userId"), // 设置要传递的参数--要和接口方提供的参数名一致 ???????????????????org.apache.axis.encoding.XMLType.XSD_STRING, ???????????????????javax.xml.rpc.ParameterMode.IN); ???????????call.addParameter(new QName(soapaction, "password"), // 设置要传递的参数 ???????????????????org.apache.axis.encoding.XMLType.XSD_STRING, ???????????????????javax.xml.rpc.ParameterMode.IN); ???????????call.setReturnType(XMLType.SOAP_STRING); // 要返回的数据类型 ???????????call.setUseSOAPAction(true); ???????????//call.setSOAPActionURI(soapaction + "hello"); ???????????String v = (String) call.invoke(new Object[] { userId, password });// 调用方法并传递参数-传递的参数和设置的参数要对应，顺序不能搞错了 ???????????System.out.print(v);//打印结果（我设置的接收格式为json字符串，这边直接打印出来） ???????}catch (Exception ex){ ???????????ex.printStackTrace(); ???????} ???}}webservice接口调用
原文地址：https://www.cnblogs.com/lensener/p/10592211.html