使用Newtonsoft.Json反序列化收到的字串为JObject或其它支持的数据模型，有时错误，提示如下：
Bad JSON escape sequence: \c. Path ‘idno‘, line 5, position 34.
甚纳闷之。遂搜索资料，略有小获，其非法分界符所致。合法的分隔符为：
以此为依据，对字串做正则替换，问题解决，录代码以记之。
???????static void Main(string[] args) ???????{ ???????????string s = @" ???????????{ ???????????????""name"": ""王艳"", ???????????????""sex"": ""女"", ???????????????""idno"": ""34*****\c0"", ???????????????""addr"": ""安徽省"", ???????????????""telephone"": ""no number"", ???????????????""thumbnail"": ""e:\docs\person\thumbnail\wy.jpg"", ???????????????""Age"": 27, ???????????????""DeptName"": ""姚江\R中心"" ???????????} ???????????"; ???????????//\加bfrnt\/‘"为合法分隔符，其它不是，替换 ???????????string pattern = @"(\\[^bfrnt\\/‘\""])"; ???????????s = Regex.Replace(s, pattern, "\\$1"); ???????????var jo = JsonConvert.DeserializeObject<JObject>(s); ???????????Console.WriteLine(jo.ToString()); ???????????Console.ReadLine(); ???????}结果如图：
参考资料：
How to escape special characters in building a JSON string? - Stack Overflow
Bad JSON escape sequence: \l. Path 'Transforms[0].Path', line 3, position 45. · Issue #343 · mmanela/chutzpah
Newtonsoft.Json反序列化(Deserialize)报错问题
原文地址：https://www.cnblogs.com/crwy/p/10172373.html