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aJax get和post

发布时间:2023-09-06 02:20责任编辑:苏小强关键词:暂无标签
<%@ page language="java" pageEncoding="utf-8"%><!DOCTYPE html><html> ???<head> ???????<meta http-equiv="Content-Type" content="text/html;charset=utf-8"> ???????<title>aJaxRequest!!!</title> ???????<script type="text/javascript"> ???????function ajaxReq(){ ???????????//获取用户请求数据 ???????????var uname=document.getElementById("uname").value; ???????????var data="uname="+uname; ???????????//创建ajax引擎对象 ???????????var ajax; ???????????if(window.XMLHttpRequest){ ???????????????ajax=new XMLHttpRequest(); ???????????}else if(window.ActiveXObject){ ???????????????ajax=new ActiveXObject("Msxml2.XMLHTTP"); ???????????} ???????????//复写onreadystatechange函数 ???????????ajax.onreadystatechange=function(){ ???????????????//判断ajax状态码 ???????????????if(ajax.readyState==4){ ???????????????????//判断响应状态码 ???????????????????if(ajax.status==200){ ???????????????????????//获取响应内容 ???????????????????????var result=ajax.responseText; ???????????????????????//处理响应内容 ???????????????????????alert(result); ???????????????????} ???????????????????} ???????????????} ???????????????//get方法 ???????????//ajax.open("get","ajaxServlet",true); ???????????//ajax.send(null); ???????????//pos方法 ???????????ajax.open("post","ajaxServlet",true); ???????????ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); ???????????ajax.send(data); ???????????} ???????</script> ???????<style type="text/css"> ???????????#myDiv{ ???????????????border:solid 4px; ???????????????width:100px; ???????????????height:100px; ???????????} ???????????????</style> ???</head> ???<body> ???????<h3>aJax!!</h3> ???????<input id="uname" type="text" name="uname" value=""> ???????<button id="myButton" onclick="ajaxReq()" />show!!!</button> ???????<div id="myDiv"></div> ???</body></html>

aJax get和post

原文地址:https://www.cnblogs.com/lastingjava/p/9893164.html

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