今天同事用的以前的获取url地址参数获取不到.以前的方法失效了.后面发现是正则表达式bug:
第一种获取方法(针对普通情况的一般够用):
function getQueryString(name) { ???var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); ???var reg_rewrite = new RegExp("(^|/)" + name + "/([^/]*)(/|$)", "i"); ???var r = window.location.search.substr(1).match(reg); ???var q = window.location.pathname.substr(1).match(reg_rewrite); ???if(r != null){ ???????return unescape(r[2]); ???}else if(q != null){ ???????return unescape(q[2]); ???}else{ ???????return null; ???}}
第二种获取方法:
这样的url地址获取不到:file:///Users/wanghong/work/ziku/youle/dist/index.html?sourceType=Tsingtao_beer_activity#/welcome?toPath=file%3A%2F%2F%2FUsers%2Fwanghong%2Fwork%2Fziku%2Fyoule%2Fdist%2Findex.html%3FsourceType%3DTsingtao_beer_activity%23%2F/** * 获取指定的URL参数值 * URL:http://www.quwan.com/index?name=tyler * 参数：paramName URL参数 * 调用方法:getParam("name") * 返回值:tyler */function getParam(paramName) { ???paramValue = "", isFound = !1; ???if (this.location.search.indexOf("?") == 0 && this.location.search.indexOf("=") > 1) { ???????arrSource = unescape(this.location.search).substring(1, this.location.search.length).split("&"), i = 0; ???????while (i < arrSource.length && !isFound) arrSource[i].indexOf("=") > 0 && arrSource[i].split("=")[0].toLowerCase() == paramName.toLowerCase() && (paramValue = arrSource[i].split("=")[1], isFound = !0), i++ ???} ???return paramValue == "" && (paramValue = null), paramValue}
大家都尝试一下.元宵节快乐
获取地址栏URL中参数, getQuerySting()方法
原文地址：https://www.cnblogs.com/luosiding/p/8494922.html