http_build_query 字符串拼接
产生一个urlencode之后的请求字符串。
1.将数组转化成url问号（?）后的字符串
1 <?php 2 ??$date=array( 3 ??????????‘name‘=>‘tane‘, 4 ??????????‘sex‘ =>1, 5 ??????????‘job‘ => ‘officer‘ 6 ??????????‘text‘ =>‘hello world‘ 7 ??); 8 ??echo http_build_query($date); 9 ??//输出 name=tane&sex=1&job=officer&text=hello+world10 ?>
2.http_build_query() 添加数字下标
$data = array(‘name‘, ‘tane‘, ‘sex‘, ?‘job‘ => ‘officer‘, ‘text‘ =>‘hello world‘); ??echo http_build_query($date,‘remot_‘); ??//输出 remot_0=name&remote_1=tane&remot_2=sex&job=officer&text=hello+world
3.http_build_query() 使用复杂的数组
<?php $data = array(‘user‘=>array(‘name‘=>‘Bob Smith‘,‘age‘=>47,‘sex‘=>‘M‘,‘dob‘=>‘5/12/1956‘), ?????????????????‘pastimes‘=>array(‘golf‘, ‘opera‘, ‘poker‘, ‘rap‘), ????????????? ‘children‘=>array(‘bobby‘=>array(‘age‘=>12,‘sex‘=>‘M‘),‘sally‘=>array(‘age‘=>8,‘sex‘=>‘F‘<br>),‘CEO‘); echo http_build_query($data, ‘flags_‘); /* 输出：（为了可读性对其进行了折行） ??????user[name]=Bob+Smith&user[age]=47&user[sex]=M&user[dob]=5%1F12%1F1956& ??????pastimes[0]=golf&pastimes[1]=opera&pastimes[2]=poker&pastimes[3]=rap& ??????children[bobby][age]=12&children[bobby][sex]=M&children[sally][age]=8& ??????children[sally][sex]=F&flags_0=CEO ??? 注意：只有基础数组中的数字下标元素“CEO”才获取了前缀，其它数字下标元素（如 ??? pastimes 下的元素）则不需要为了合法的变量名而加上前缀。 */?>
4.http_build_query()使用对象
<?php ???class myClass { ??????var $foo; ??????var $baz; ??????function myClass() { ???????????$this->foo = ‘bar‘; ???????????$this->baz = ‘boom‘; ??????} ???} ???$data = new myClass(); ???echo http_build_query($data); ???/* 输出：foo=bar&baz=boom*/?> ?????http_build_query 字符串拼接
原文地址：https://www.cnblogs.com/tine/p/8461203.html