兼容不带参数等情况
function getUrlParam(){ ???????var params = {}; ???????var search = location.search; ???????search = /\?/.test(search) && search.split("?")[1]; ???????var searchs = /\&/.test(search) ? search.split("&") : [search]; ???????for(var i = 0 ; i < searchs.length ; i++){ ???????????if(/\=/.test(searchs[i])){ ???????????????var item = searchs[i].split("="); ???????????????params[item[0]] = item[1]; ???????????}; ???????}; ???????return params; ???};
解析url中参数
原文地址:http://www.cnblogs.com/wangxiaohang/p/7646781.html