直接贴代码！我也测试通过！ 一切看注释！ 谢谢！
<%@ WebHandler Language="C#" class="Handler" %>using System;using System.Web;using System.Text;public class Handler : IHttpHandler { ???????public void ProcessRequest (HttpContext context) { ???????context.Response.ContentType = "text/plain"; ???????string id = "0"; ???????//判断提交方式 ???????if (context.Request.RequestType.ToLower() == "get") ???????{ ???????????id = context.Request.QueryString["id"]; ???????} ???????else ???????{ ???????????id = context.Request.Form["id"]; ???????} ???????????????string name = @"jinho‘s good \"" you"; ???????/** ????????* 今天暂时用手动创建个json字符串类型,其实.net中有 ????????* System.Runtime.Serialization.Json.DataContractJsonSerializer这个类来把 ????????* 实体对象转换为json字符串! 改天再用那种方式写个吧! ????????* 自己也学习学习[更多关于json介绍!google一下多了是] ????????* */ ???????StringBuilder sb = new StringBuilder("{"); ???????sb.Append("id:"+id); ???????/* ????????* 注意但属性值为字符串的时候需要有‘号或者"号[‘字符串‘] ????????* 当 参数 name 又含 有单引号或者双引号 就会出错了！[截断了字符串] ????????* 在这里sb.Append(",name:‘escape(" + name + ")‘"); 用js的escape也不行 ????????* context.Server.HtmlEncode();,context.Server.UrlEncode();也不行 ????????* 可以看看这里 ????????* escape("‘") = %27 可以在js用 unescape("‘") 就还原了 ????????* escape(""") = %22 嘿嘿,用这个方法也是我的无奈之举! ????????* 谁有好的方法记得告诉我哦！ 先谢谢了! ????????* 问题已解决：http://www.cnblogs.com/jinho/archive/2010/05/07/1729586.html ????????* */ ???????sb.Append(",name:‘" + name.Replace("‘", "%27").Replace("\"", "%22") + "‘"); ????????sb.Append(",age:22"); ???????sb.Append("}"); ???????//输出 json 字符串 ???????context.Response.Write(sb.ToString()); ???????context.Response.End(); ???} ????public bool IsReusable { ???????get { ???????????return false; ???????} ???}}<%@ Page Language="C#" %><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><script runat="server"></script><html xmlns="http://www.w3.org/1999/xhtml"><head runat="server"> ???<title>前台</title></head><body> ???<form id="form1" runat="server"> ???<asp:scriptmanager runat="server" ID="sm" /> ???<script type="text/javascript"> ???????function ajaxFunction() { ???????????var xmlHttp; ???????????try { ???????????????// Firefox, Opera 8.0+, Safari ???????????????xmlHttp = new XMLHttpRequest(); ???????????} ???????????catch (e) { ???????????????// Internet Explorer ???????????????try { ???????????????????xmlHttp = new ActiveXObject("Msxml2.XMLHTTP"); ???????????????} ???????????????catch (e) { ???????????????????try { ???????????????????????xmlHttp = new ActiveXObject("Microsoft.XMLHTTP"); ???????????????????} ???????????????????catch (e) { ???????????????????????alert("您的浏览器不支持AJAX！"); ???????????????????????return false; ???????????????????} ???????????????} ???????????} ???????????return xmlHttp; ???????}</script> ???<script type="text/javascript"> ???????var xmlhttp = null; ???????function loadJsonData() { ???????????xmlhttp = ajaxFunction(); ???????????if (xmlhttp != null) { ???????????????xmlhttp.onreadystatechange = state_Change; ???????????????var data = "id=231"; ???????????????//把这两句注释,看看下面的POST提交方式 ???????????????xmlhttp.open("GET", "Handler.ashx?" + data, true); ???????????????xmlhttp.send(null); ???????????????/* ???????????????xmlhttp.open("POST", "Handler.ashx", true); ???????????????//如果使用POST提交 不设置这条语句,url页面 Request.Form["key"] 是取不到值的！ ???????????????//这句我也不知道为什么要设置,网上找到的！[GET提交可以不设置,但需要把参数拼接到URL] ???????????????xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); ???????????????xmlhttp.send(data); //如果是post提交,需要把数据发送过去 ???????????????*/ ???????????} ???????????else { ???????????????alert("Your browser does not support XMLHTTP."); ???????????} ???????} ???????function state_Change() { ???????????if (xmlhttp.readyState == 4) {// 4 = "loaded" ???????????????if (xmlhttp.status == 200) {// 200 = "OK" ???????????????????eval("var s = " + xmlhttp.responseText); ???????????????????$get("divDisplay").innerHTML = "ID" + s.id + "Name:" + unescape(s.name) + "Age:" + s.age; ???????????????} ???????????????else { ???????????????????alert("Error:" + xmlhttp.statusText); ???????????????} ???????????} ???????}</script> ???<div> ???<input type="button" value="GetJson" onclick="loadJsonData();" /> ???<div id="divDisplay"></div> ???</div> ???</form></body></html>AJAX提交到Handler.ashx一般处理程序返回json数据-转
原文地址：https://www.cnblogs.com/asdyzh/p/9785376.html