在项目之中我们经常会涉及到字符串和各种对象的转换，为此特地整理了一下常用的转换方法
一、基于com.google.code.gson封装的json转换工具类
1. 在pom.xml文件里面引入gson的依赖
???????<dependency> ???????????<groupId>com.google.code.gson</groupId> ???????????<artifactId>gson</artifactId> ???????????<version>2.8.3</version> ???????</dependency>
2. 编写工具类GsonUtil
package com.json.util;import com.google.gson.Gson;import com.google.gson.reflect.TypeToken;import java.util.List;import java.util.Map;/** * ?* @Description: 基于com.google.code.gson封装的json转换工具类 * @author lgs * @date 2018年5月30日 * */public class GsonUtil { ???private static Gson gson = null; ???static { ???????if (gson == null) { ???????????gson = new Gson(); ???????} ???} ???private GsonUtil() { ???} ???/** ????* 对象转成json ????* ????* @param object ????* @return json ????*/ ???public static String gsonString(Object object) { ???????String gsonString = null; ???????if (gson != null) { ???????????gsonString = gson.toJson(object); ???????} ???????return gsonString; ???} ???/** ????* Json转成对象 ????* ????* @param gsonString ????* @param cls ????* @return 对象 ????*/ ???public static <T> T gsonToBean(String gsonString, Class<T> cls) { ???????T t = null; ???????if (gson != null) { ???????????t = gson.fromJson(gsonString, cls); ???????} ???????return t; ???} ???/** ????* json转成list<T> ????* ????* @param gsonString ????* @param cls ????* @return list<T> ????*/ ???public static <T> List<T> gsonToList(String gsonString, Class<T> cls) { ???????List<T> list = null; ???????if (gson != null) { ???????????list = gson.fromJson(gsonString, new TypeToken<List<T>>() { ???????????}.getType()); ???????} ???????return list; ???} ???/** ????* json转成list中有map的 ????* ????* @param gsonString ????* @return List<Map<String, T>> ????*/ ???public static <T> List<Map<String, T>> gsonToListMaps(String gsonString) { ???????List<Map<String, T>> list = null; ???????if (gson != null) { ???????????list = gson.fromJson(gsonString, new TypeToken<List<Map<String, T>>>() { ???????????}.getType()); ???????} ???????return list; ???} ???/** ????* json转成map的 ????* ????* @param gsonString ????* @return Map<String, T> ????*/ ???public static <T> Map<String, T> gsonToMaps(String gsonString) { ???????Map<String, T> map = null; ???????if (gson != null) { ???????????map = gson.fromJson(gsonString, new TypeToken<Map<String, T>>() { ???????????}.getType()); ???????} ???????return map; ???}}二、基于阿里的fastjson封装的json转换工具类
1. 在pom.xml文件里面引入fastjson的依赖
???????<dependency> ???????????<groupId>com.alibaba</groupId> ???????????<artifactId>fastjson</artifactId> ???????????<version>1.2.4</version> ???????</dependency>
2. 编写工具类FastJsonUtils
package com.json.util;import java.util.List;import java.util.Map;import com.alibaba.fastjson.JSON;import com.alibaba.fastjson.TypeReference;/** * ?* @Description: 基于fastjson封装的json转换工具类 * @author lgs * @date 2018年5月30日 * */public class FastJsonUtils { ???/** ????* 功能描述：把JSON数据转换成指定的java对象 ????* @param jsonData JSON数据 ????* @param clazz 指定的java对象 ????* @return 指定的java对象 ????*/ ???public static <T> T getJsonToBean(String jsonData, Class<T> clazz) { ???????return JSON.parseObject(jsonData, clazz); ???} ???/** ????* 功能描述：把java对象转换成JSON数据 ????* @param object java对象 ????* @return JSON数据 ????*/ ???public static String getBeanToJson(Object object) { ???????return JSON.toJSONString(object); ???} ???/** ????* 功能描述：把JSON数据转换成指定的java对象列表 ????* @param jsonData JSON数据 ????* @param clazz 指定的java对象 ????* @return List<T> ????*/ ???public static <T> List<T> getJsonToList(String jsonData, Class<T> clazz) { ???????return JSON.parseArray(jsonData, clazz); ???} ???/** ????* 功能描述：把JSON数据转换成较为复杂的List<Map<String, Object>> ????* @param jsonData JSON数据 ????* @return List<Map<String, Object>> ????*/ ???public static List<Map<String, Object>> getJsonToListMap(String jsonData) { ???????return JSON.parseObject(jsonData, new TypeReference<List<Map<String, Object>>>() { ???????}); ???}}Json转换工具类（基于google的Gson和阿里的fastjson）
原文地址：https://www.cnblogs.com/leeSmall/p/9114134.html