// 两种获取方法function GetQueryString(parameter) { ???var reg = new RegExp("(^|&)" + parameter + "=([^&]*)(&|$)"); ???var r = window.location.search.substr(1).match(reg); ???if (r != null) { ???????if (parameter == "deId") { ???????????$("#deId").val(r[2]); ???????} ???????if (parameter == "deName") { ???????????$("#deName").val(decodeURI(r[2]));//解决中文乱码 ???????} ???}}function getRequest() { ???????var url = location.search; //获取url中"?"符后的字串 ???????var theRequest = new Object(); ???????if(url.indexOf("?") != -1) { ???????????var str = url.substr(1); ???????????var strs = str.split("&"); ???????????for(var i = 0; i < strs.length; i++) { ???????????????theRequest[strs[i].split("=")[0]] = decodeURIComponent(strs[i].split("=")[1]); ???????????} ???????} ???????return theRequest;}// 如果获取时出现乱码请查看是不是使用了unescape来解码url的参数，替换为decodeURIComponent或decodeURI即可，unescape和escape即将被废弃// 另外：encodeURIComponent或encodeURI编码方式相同，对于整个url来说，前者会编码url中的; / ? : @ & = + $ , # 后者不会编码js获取url参数，以及中文乱码问题
原文地址：https://www.cnblogs.com/benlightning/p/9532970.html