dom结构：在一定条件下想默认选中第二个选项卡
<div id="segmentedControl" class="mui-segmented-control mui-segmented-control-inverted mui-segmented-control-negative addressslider" style="border-bottom:1px solid #CCC;"> ????<a class="mui-control-item mui-active" href="#item1"> ???????选择地址 ????</a> ????<a class="mui-control-item" href="#item2" id="header2"> ???????新增地址 ????</a> </div> <div id="item1" class="mui-control-content mui-active" style="height:320px;"> ???<div class="mui-scroll-wrapper"> ???????<div class="mui-scroll"> ???????????第二个选项卡，有滚动 ???????</div> ???????<!--<div class="mui-scrollbar mui-scrollbar-vertical" style="transition-duration: 500ms; opacity: 0;"><div class="mui-scrollbar-indicator" style="transition-duration: 0ms; display: block; height: 25px; transform: translate3d(0px, 0px, 0px) translateZ(0px); transition-timing-function: cubic-bezier(0.165, 0.84, 0.44, 1);"></div></div>--> ???????????????????????</div></div><div id="item2" class="mui-control-content" style="height:320px;"> ?????第二个选项卡</div>
亲测可用
????//模拟第二个选项卡点击
?????????mui.trigger(document.getElementById("header2"),‘touchstart‘);
?mui.trigger(document.getElementById("header2"),‘tap‘);
注意：
mui.trigger 第一个参数应该是dom对象，如果用jq需要转换成dom
依次触发touchstart tap两个事件才可以
mui的选项卡js选中指定项
原文地址：https://www.cnblogs.com/djiz/p/8215123.html