80. Remove Duplicates from Sorted Array II（js）

80. Remove Duplicates from Sorted Array II

Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example 1:

Given nums = [1,1,1,2,2,3],Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3 respectively.It doesn‘t matter what you leave beyond the returned length.

Example 2:

Given nums = [0,0,1,1,1,1,2,3,3],Your function should return length = 7, with the first seven elements of nums being modified to 0, 0, 1, 1, 2, 3 and 3 respectively.It doesn‘t matter what values are set beyond the returned length.
题意：给定一个数组，操作数组后的每项出现的次数不超过3次，返回这个数组的长度
代码如下：

/** * @param {number[]} nums * @return {number} */var removeDuplicates = function(nums) { ???var i=0; ???nums.forEach(item=>{ ???????if(i<2 || item>nums[i-2]) ???????????nums[i++]=item; ???}) ???return i;};

80. Remove Duplicates from Sorted Array II（js）

原文地址：https://www.cnblogs.com/xingguozhiming/p/10581744.html