2017-09-25
refer : https://docs.microsoft.com/en-us/aspnet/core/mvc/models/file-uploads
https://www.codeproject.com/Articles/1203408/Upload-Download-Files-in-ASP-NET-Core
这里只说说小文件上传.
先看看前端 js 代码
<input id="inputFile" type="file" /><script> ???document.getElementById(‘inputFile‘).addEventListener(‘change‘, (e) => { ???????????????let files = e.target.files; ???????????????let formData = new FormData(); ???????formData.append("file", files[0]); ???????let http = new XMLHttpRequest(); ???????http.open(‘POST‘, ‘/upload-file‘, true); ???????http.send(formData); ????}, false); </script>
如果要上传多个文件就 append 多几个就是了
c#
public class UploadFileData{ ???public IFormFile file { get; set; }}[Area("Web")]public class UploadController : Controller{ ???public UploadController( ???????????IHostingEnvironment environment ???) ???{ ???????this.environment = environment; ???} ???private IHostingEnvironment environment { get; set; } ???????????[HttpPost("upload-file")] ???public async Task<IActionResult> uploadFile(UploadFileData data) ???{ ???????var allFiles = Request.Form.Files; // 多文件的话可以直接从 form 拿到完 ????????var root = environment.WebRootPath; ???????var extension = Path.GetExtension(data.file.FileName); ???????var guid = Guid.NewGuid().ToString(); ???????var fullPath = $@"{root}\images\{guid + extension}"; ???????using (FileStream stream = new FileStream(fullPath, FileMode.Create)) ???????{ ???????????await data.file.CopyToAsync(stream); ???????} ????????return Ok(); ???} ???[Route("upload")] ???public async Task<IActionResult> Index() ???{ ???????return View(); ???}}
上面的是最简单的版本,创建 file 然后把 upload file stream 写入
还有一个常用的场景是, 上传图片要做 EXIF 处理.
可以用 Magick.NET 目前支持 core, 不过呢, 好像只支持 window 场景. 如果你不是 windows 可能要在等等或则用其它插件.
using (var stream = data.file.OpenReadStream())using (MagickImage image = new MagickImage(stream)){ ???ExifProfile profile = image.GetExifProfile(); ???image.Settings.SetDefine(MagickFormat.Jpeg, "sampling-factor", "4:2:0"); ???image.Strip(); //这句会把图片的所有 EXIF 洗掉 ???image.Quality = 85; ???if (profile != null) ???{ ???????ExifValue orientation = profile.Values.SingleOrDefault(v => v.Tag == ExifTag.Orientation); ???????if (orientation != null) ???????{ ???????????int orientationInt = Convert.ToInt32(orientation.Value); ???????????if (orientationInt == 6) ???????????{ ???????????????image.Rotate(90); ???????????} ???????????else if (orientationInt == 8) ???????????{ ???????????????image.Rotate(-90); ???????????} ???????????else if (orientationInt == 8) ???????????{ ???????????????image.Rotate(180); ???????????} ???????} ???????image.Write(fullPath); ???} ???else ???{ ???????image.Write(fullPath); ???}}
很简单吧.
再来一个 zip 的
using (var stream = data.file.OpenReadStream())using (var compressedFileStream = new FileStream($@"{root}\images\{guid}.zip", FileMode.Create))using (var zipArchive = new ZipArchive(compressedFileStream, ZipArchiveMode.Update, false)){ ???var zipEntry = zipArchive.CreateEntry(data.file.FileName); ???using (var zipEntryStream = zipEntry.Open()) ???{ ???????stream.CopyTo(zipEntryStream); ???}}
core 支持 ZipArchive 哦
下载也很容易
public UploadController( ???????IHostingEnvironment environment, ???????IContentTypeProvider contentTypeProvider){ ???this.environment = environment; ???this.contentTypeProvider = contentTypeProvider;}private IHostingEnvironment environment { get; set; }private IContentTypeProvider contentTypeProvider { get; set; } ???????[HttpGet("download-file")]public FileResult downloadFile(string name, string display){ ???string contentType; ???contentTypeProvider.TryGetContentType(name, out contentType); ???HttpContext.Response.ContentType = contentType; ???string path = environment.WebRootPath + @"\images\" + name; // 注意哦, 不要像我这样直接使用客户端的值来拼接 path, 危险的 ????FileContentResult result = new FileContentResult(System.IO.File.ReadAllBytes(path), contentType) ???{ ???????FileDownloadName = display ???}; ???return result;}
html
<a href="/download-file?name=123.jpg&display=aaa.jpg" download ?>download</a>
Asp.net core 学习笔记 ( upload/download files 文件上传与下载 )
原文地址:http://www.cnblogs.com/keatkeat/p/7594496.html