PHP面向对象编程题(方法的实践)

<?phpheader(‘content-type:text/html;charset=utf-8‘);/*设计一个peron类(有名字,年龄和蛋糕三个属性) ???蛋糕一共1000块,是所有人共享的, ???创建唐僧师徒四人,他们每人都吃蛋糕,唐僧每天吃3块,悟空吃五块,沙僧吃九块,猪八戒吃30块(编写一个eat方法来吃) ???问两天后,还剩多少块蛋糕(编写一个showCake()来显示) ???请计算,蛋糕一共可以吃多少天*/class Person{ ???public $name; ???public $age; ???/*因为是共享的,因此设置static*/ ???protected static $cakeNum = 1000; ???????/*构造函数*/ ???public function __construct($name,$age){ ???????$this->name = $name; ???????$this->age = $age; ???????} ???/*编写eat方法*/ ?//传入要吃的蛋糕 ???public function eat($num){ ???????//判断一下蛋糕是否够吃 ???????if(self::$cakeNum >= $num){ ???????????self::$cakeNum -= $num; ???????}else{ ???????????echo ‘<br>蛋糕不够吃了‘; ???????} ???} ???//编写一个方法,显示还有多少块蛋糕 ???public function showNum(){ ???????echo ‘<br> 当前还有 ‘ . self::$cakeNum . ‘蛋糕.‘; ???}}//使用//1.创建四个对象$monk = new Person(‘唐僧‘,30);$monkey = new Person(‘悟空‘,500);$pig = new Person(‘八戒‘,400);$sMonk = new Person(‘沙僧‘,300);//2.统计2天后$day = 2 ;for($i = 0 ; $i<$day;$i++){ ???$monk->eat(3); ???$monkey->eat(5); ???$sMonk->eat(9); ???$pig->eat(30);}//3.看看还剩多少块$monk->showNum();

<?phpheader(‘content-type:text/html;charset=utf-8‘);/*设计一个peron类(有名字,年龄和蛋糕三个属性) ???蛋糕一共1000块,是所有人共享的, ???创建唐僧师徒四人,他们每人都吃蛋糕,唐僧每天吃3块,悟空吃五块,沙僧吃九块,猪八戒吃30块(编写一个eat方法来吃) ???问两天后,还剩多少块蛋糕(编写一个showCake()来显示) ???请计算,蛋糕一共可以吃多少天*/class Person{ ???public $name; ???public $age; ???/*因为是共享的,因此设置static*/ ???protected static $cakeNum = 1000; ???????/*构造函数*/ ???public function __construct($name,$age){ ???????$this->name = $name; ???????$this->age = $age; ???????} ???/*编写eat方法*/ ?//传入要吃的蛋糕 ???public function eat($num){ ???????//判断一下蛋糕是否够吃 ???????if(self::$cakeNum >= $num){ ???????????self::$cakeNum -= $num; ???????????return true; ??//如果够吃返回true ???????}else{ ???????????echo ‘<br> 当‘ .$this->name. ‘想吃‘ . $num . ‘块蛋糕时,蛋糕不够吃了‘; ???????????return false; ???//如果不够吃返回false ???????} ???} ???//编写一个方法,显示还有多少块蛋糕 ???public function showNum(){ ???????echo ‘<br> 当前还有 ‘ . self::$cakeNum . ‘蛋糕.‘; ???}}//使用//1.创建四个对象$monk = new Person(‘唐僧‘,30);$monkey = new Person(‘悟空‘,500);$pig = new Person(‘八戒‘,400);$sMonk = new Person(‘沙僧‘,300);//2.统计2天后$day = 30 ;for($i = 0 ; $i<$day;$i++){ ???//给每个人吃的时候加判断,当不够吃的时候break终止循环 ???if(!$monk->eat(3)){ ???????break; ???}; ???if(!$monkey->eat(5)){ ???????break; ???????}; ???if(!$sMonk->eat(9)){ ???????break; ???????}; ???if(!$pig->eat(30)){ ???????break; ???????};}//3.看看还剩多少块$monk->showNum();

<?phpheader(‘content-type:text/html;charset=utf-8‘);/*设计一个peron类(有名字,年龄和蛋糕三个属性) ???蛋糕一共1000块,是所有人共享的, ???创建唐僧师徒四人,他们每人都吃蛋糕,唐僧每天吃3块,悟空吃五块,沙僧吃九块,猪八戒吃30块(编写一个eat方法来吃) ???问两天后,还剩多少块蛋糕(编写一个showCake()来显示) ???请计算,蛋糕一共可以吃多少天*/class Person{ ???public $name; ???public $age; ???/*因为是共享的,因此设置static*/ ???protected static $cakeNum = 1000; ???????/*构造函数*/ ???public function __construct($name,$age){ ???????$this->name = $name; ???????$this->age = $age; ???????} ???/*编写eat方法*/ ?//传入要吃的蛋糕 ???public function eat($num){ ???????//判断一下蛋糕是否够吃 ???????if(self::$cakeNum >= $num){ ???????????self::$cakeNum -= $num; ???????????return true; ??//如果够吃返回true ???????}else{ ???????????echo ‘<br> 当‘ .$this->name. ‘想吃‘ . $num . ‘块蛋糕时,蛋糕不够吃了‘; ???????????return false; ???//如果不够吃返回false ???????} ???} ???//编写一个方法,显示还有多少块蛋糕 ???public function showNum(){ ???????echo ‘<br> 当前还有 ‘ . self::$cakeNum . ‘蛋糕.‘; ???}}//使用//1.创建四个对象$monk = new Person(‘唐僧‘,30);$monkey = new Person(‘悟空‘,500);$pig = new Person(‘八戒‘,400);$sMonk = new Person(‘沙僧‘,300);
$count_day = 0; //思路:天数从0开始,没循环一次加1,最后输出$count_daywhile(true){ ???if(!$monk->eat(3)){ ???????break; ???}; ???if(!$monkey->eat(5)){ ???????break; ???????}; ???if(!$sMonk->eat(9)){ ???????break; ???????}; ???if(!$pig->eat(30)){ ???????break; ???????}; ???$count_day ++;}echo ‘<br>蛋糕能吃多少:‘.$count_day.‘天‘;//3.看看还剩多少块$monk->showNum();