1、获取链接全部参数，以对象的形式返回
//获取url中参数function GetRequest() { ???var url = location.search; ??//获取url中"?"符后的字串 ??????var theRequest = new Object(); ???if (url.indexOf("?") != -1) ????{ ???????var str = url.substr(1); ???????strs = str.split("&"); ???????for (var i = 0; i < strs.length; i++) ????????{ ???????????theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); ???????} ???} }2、根据参数名获取链接中的参数值
function GetRequest2(key) { ???var url = location.search; ?????var theRequest = new Object(); ???if (url.indexOf("?") != -1) ????{ ???????var str = url.substr(1); ???????strs = str.split("&"); ???????for (var i = 0; i < strs.length; i++) ????????{ ???????????theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); ???????} ???} ???var value = theRequest[key]; ???return value; }JS 获取链接中的参数
原文地址：https://www.cnblogs.com/dyhao/p/9923574.html