1 <!DOCTYPE html> 2 <html> 3 ????<head> 4 ????????<meta charset="utf-8" /> 5 ????????<meta name="viewport" content="width=device-width, initial-scale=1"> 6 ????????<title></title> 7 ????????<script src="https://cdn.staticfile.org/jquery/3.3.1/jquery.js"></script> 8 ????</head> 9 ????<body>10 11 ????????<script type="text/javascript">12 ????????????var jsonObj1 = {13 ????????????????a: 214 ????????????};15 ????????????var jsonObj2 = {16 ????????????????b: 2,17 ????????????????c: 3,18 ????????????????d: 419 ????????????};20 21 ????????????let mergeJsonObject = function(jsonbject1, jsonbject2) {22 ????????????????let resultJsonObject = {};23 ????????????????for (let attr in jsonbject1) {24 ????????????????????resultJsonObject[attr] = jsonbject1[attr];25 ????????????????}26 ????????????????for (let attr in jsonbject2) {27 ????????????????????resultJsonObject[attr] = jsonbject2[attr];28 ????????????????}29 ????????????????return resultJsonObject;30 ????????????};31 ????????????console.log(mergeJsonObject(jsonObj1, jsonObj2))32 ????????</script>33 ????</body>34 </html>同上一篇，但只适用于键名不同的json
原文地址：https://www.cnblogs.com/yg-home/p/9875930.html