在开发中，有时我们需要在View层中拿到Model返回的数据并且是一个Json对象，那么我们就可以利用Newtonsoft.Json.JsonConvert.SerializeObject(Model)将Model层反序列化，由于js拿到反序列化的数据后一些特殊字符还需要处理，如：双引号"反序列化后会变成"，所以要将其替换成",str.replace(/"/g,"\"")，然后再用js函数JSON.parse将其转换，就得到一个Json对象
后台C#代码：
namespace MvcApplication1.Controllers{ ???public class HomeController : Controller ???{ ???????public ActionResult Index() ???????{ ???????????View_News View_News = new View_News(); ???????????List<News> NewsList = new List<News>(); ???????????NewsList.Add(new News() { Url = "www.baidu.com", Image = "/Resource/Skin02", Title = "Tom" }); ???????????NewsList.Add(new News() { Url = "www.taobao.com", Image = "/Resource/Skin03", Title = "Jim" }); ???????????NewsList.Add(new News() { Url = "www.jd.com", Image = "/Resource/Skin04", Title = "Jess" }); ???????????View_News.NewsList = NewsList; ???????????return View(View_News); ???????} ???} ???public class View_News ???{ ???????public List<News> NewsList { get; set; } ???} ???public class News ???{ ???????public string Url { get; set; } ???????public string Image { get; set; } ???????public string Title { get; set; } ???}}前台代码：
@model MvcApplication1.Controllers.View_News@{ ???Layout = null; ???string str = Newtonsoft.Json.JsonConvert.SerializeObject(Model.NewsList);}<!DOCTYPE html><html><head> ???<meta name="viewport" content="width=device-width" /> ???<title>Index</title> ???<script src="~/Scripts/jquery-1.8.2.min.js"></script> ???<script type="text/javascript"> ???????var picData = {}; ???????var theString = ‘@(str)‘; ???????theString = theString.replace(/"/g,"\""); ???????var temp = JSON.parse(theString); ???????picData.news = temp; ???????console.log(picData); ???</script></head>输出结果：
MVC之Model转Json
原文地址：https://www.cnblogs.com/zhangruisoldier/p/8556153.html