获取date类型
var type = _xAxis[0].split(/-|:|\s/).length;
按时间粒度获取date的时间差
???function getDateDiffByType(newDate,endDate,type){ ???????newDate = new Date(newDate) == ‘Invalid Date‘ ? newDate+‘:00‘ : newDate; ???????endDate = new Date(endDate) == ‘Invalid Date‘ ? endDate+‘:00‘ : endDate; ???????var dateDiff = new Date(endDate)-new Date(newDate); ???????var _date = new Date(dateDiff); ???????var year = _date.getFullYear() - 1970; ???????var month = _date.getMonth(); ???????switch (type) { ???????????case 1: { ???????????????return year; ???????????????break; ???????????} ???????????case 2: { ???????????????return month+year*12; ???????????????break; ???????????} ???????????case 3: { ???????????????return dateDiff/1000/60/60/24; ???????????????break; ???????????} ???????????case 4: { ???????????????return dateDiff/1000/60/60; ???????????????break; ???????????} ???????????case 5: { ???????????????return dateDiff/1000/60; ???????????????break; ???????????} ???????????case 6: { ???????????????return dateDiff/1000; ???????????????break; ???????????} ???????} ???} 附：date按时间粒度格式化
function dateFmtByType( _date,_type) {_date = new Date(_date) == ‘Invalid Date‘ ? _date+‘:00‘ : _date;//"2017-02-12 12"是Invalid Datevar date = new Date(_date);var fmt = ["yyyy","yyyy-MM","yyyy-MM-dd","yyyy-MM-dd hh","yyyy-MM-dd hh:mm","yyyy-MM-dd hh:mm:ss"];return date.dateFormat(fmt[_type-1]);}附：date格式化代码("yyyy-MM-dd hh:mm:ss")
Date.prototype.dateFormat = function(fmt) ??{ //author: meizz ????var o = { ??????"M+" : this.getMonth()+1, ????????????????//月份 ??????"d+" : this.getDate(), ???????????????????//日 ??????"h+" : this.getHours(), ??????????????????//小时 ??????"m+" : this.getMinutes(), ????????????????//分 ??????"s+" : this.getSeconds(), ????????????????//秒 ??????"q+" : Math.floor((this.getMonth()+3)/3), //季度 ??????"S" ?: this.getMilliseconds() ????????????//毫秒 ????}; ????if(/(y+)/.test(fmt)) ??????fmt=fmt.replace(RegExp.$1, (this.getFullYear()+"").substr(4 - RegExp.$1.length)); ????for(var k in o) ??????if(new RegExp("("+ k +")").test(fmt)) ????fmt = fmt.replace(RegExp.$1, (RegExp.$1.length==1) ? (o[k]) : (("00"+ o[k]).substr((""+ o[k]).length))); ????return fmt; ??}
JS如何按时间粒度获取date的时间差
原文地址：https://www.cnblogs.com/Begin-Vic/p/8134815.html