Django REST framework反向生成url

Django REST framework是一个基于Django的框架,REST framework又是怎么反向生成url的呢??

在前面的例子中,知道在REST framework中有6种版本控制的方式,进入任意一种版本控制的源码中,

class QueryParameterVersioning(BaseVersioning): ???""" ???GET /something/?version=0.1 HTTP/1.1 ???Host: example.com ???Accept: application/json ???""" ???invalid_version_message = _(‘Invalid version in query parameter.‘) ???def determine_version(self, request, *args, **kwargs): ???????version = request.query_params.get(self.version_param, self.default_version) ???????if not self.is_allowed_version(version): ???????????raise exceptions.NotFound(self.invalid_version_message) ???????return version ???def reverse(self, viewname, args=None, kwargs=None, request=None, format=None, **extra): ???????url = super(QueryParameterVersioning, self).reverse( ???????????viewname, args, kwargs, request, format, **extra ???????) ???????if request.version is not None: ???????????return replace_query_param(url, self.version_param, request.version) ???????return url

可以看到每一个版本控制的类中也都有reverse方法,由此可以了REST framework也是使用reverse的方式来反向生成url

新建一个Django项目,在项目的app中导入rest-framework

在settings.py文件中做如下配置

INSTALLED_APPS = [ ???‘django.contrib.admin‘, ???‘django.contrib.auth‘, ???‘django.contrib.contenttypes‘, ???‘django.contrib.sessions‘, ???‘django.contrib.messages‘, ???‘django.contrib.staticfiles‘, ???‘app01.apps.App01Config‘, ???‘rest_framework‘,]REST_FRAMEWORK = { ???‘DEFAULT_VERSIONING_CLASS‘: ‘rest_framework.versioning.URLPathVersioning‘, ???‘VERSION_PARAM‘: "version", ???‘DEFAULT_VERSION‘: ‘V1‘, ???‘ALLOWED_VERSIONS‘: [‘v1‘, ‘v2‘]}

在urls.py文件中添加路由信息

from django.conf.urls import urlfrom django.contrib import adminfrom app01 import viewsurlpatterns = [ ???url(r‘^admin/‘, admin.site.urls), ???url(r‘^(?P<version>\w+)/users/$‘,views.UsersView.as_view(),name="test1"),]

在views.py文件中定义UserView的类

from django.shortcuts import render,HttpResponsefrom rest_framework.views import APIViewfrom rest_framework.versioning import URLPathVersioningclass UsersView(APIView): ???def get(self,request,*args,**kwargs): ???????????????# 打印版本信息 ???????print("request.version:",request.version) ???????????????# reverse方法有一个viewname参数,在这里定义为urls.py中定义的name ???????print(request.versioning_scheme.reverse("test1",request=request)) ???????return HttpResponse("aaaa") 

此时,在浏览器中输入http://127.0.0.1:8000/v1/users/,在服务端后台打印信息如下

request.version: v1http://127.0.0.1:8000/v1/users/

再把浏览器中的url更换为http://127.0.0.1:8000/v2/users/,服务端后台的打印信息又变成了

request.version: v2http://127.0.0.1:8000/v2/users/

可以看到打印出了正确的版本,并且反向生成url也已经成功了