js函数式编程curry与compose实现

//自行实现以下curry函数和compose

//curry

function curry(fn) {
 ???return function aa (...arg) {
 ???????if (arg.length >= fn.length) {
 ???????????return fn(...arg);
 ???????} else {
 ???????????return aa.bind(null, ...arg);
 ???????}
 ???}
}

const curry = (fn) => aa = (...arg) => arg.length >= fn.length ? fn(...arg): aa.bind(null, ...arg);
// compose

function compose(...arr) {
 ???return function (...arr2) {
 ???????(function aa(n) {
 ???????????if (n < arr.length -1) {
 ???????????????return arr[n](aa(++n))
 ???????????} else {
 ???????????????return arr[n](...arr2);
 ???????????}
 ???????})(0)
 ???}
}

const compose = (...arr) => (...arr2) => ((aa = (n) => n < arr.length - 1 ? arr[n](aa(++n)): arr[n](...arr2))(0));

js函数式编程curry与compose实现

原文地址：https://www.cnblogs.com/sgqwjr/p/10294176.html