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用Servlet返回JSON文本动态创建DataGrid

发布时间:2023-09-06 02:25责任编辑:胡小海关键词:暂无标签
<%@ page language="java" pageEncoding="UTF-8"%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> ?<head> ???<title>用Servlet返回JSON文本动态创建DataGrid</title> ???<!-- 引入css文件,无顺序 --> ???<link rel="stylesheet" href="themes/icon.css" type="text/css"></link> ???<link rel="stylesheet" href="themes/default/easyui.css" type="text/css"></link> ?????<!-- 引入js文件,有顺序 --> ???<script type="text/javascript" src="js/jquery.min.js"></script> ???<script type="text/javascript" src="js/jquery.easyui.min.js"></script> ???<script type="text/javascript" src="js/easyui-lang-zh_CN.js"></script> ?</head> ?<body> ???<table id="dg"></table> ???<script type="text/javascript"> ???????$("#dg").datagrid({ ???????????url : "${pageContext.request.contextPath}/UserServlet?time="+new Date().getTime(), ???????????columns : ?[[ ???????????????????????????????????{field:‘id‘,title:‘编号‘,width:100}, ???????????????????????????????????{field:‘name‘,title:‘姓名‘,width:100}, ???????????????????????????????????{field:‘sal‘,title:‘薪水‘,width:100}, ???????????????????????????????{field:‘sex‘,title:‘性别‘,width:100} ??????????????????????????????]], ???????????fitColumns : true, ???????????singleSelect : true, ???????????pagination : true, ???????????pageSize : 2, ???????????pageList : [2,4] ???????????????????}); ???</script> ?????</body></html>
package loaderman.bean2json;import java.io.IOException;import java.io.PrintWriter;import java.util.ArrayList;import java.util.LinkedHashMap;import java.util.List;import java.util.Map;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import net.sf.json.JSONArray;/** * 用Servlet返回JSON文本动态创建DataGrid * * @author AdminTC */public class UserServlet extends HttpServlet { ???public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ???????this.doPost(request, response); ???} ???public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ???????request.setCharacterEncoding("UTF-8"); ???????//收集DataGrid向服务器发送的参数--page(当前页号) ???????String page = request.getParameter("page"); ???????System.out.println("page=" + page); ???????//收集DataGrid向服务器发送的参数--rows(当前需要显示的记录数) ???????String rows = request.getParameter("rows"); ???????System.out.println("rows=" + rows); ???????List<User> userList = new ArrayList<User>(); ???????userList.add(new User(1, "哈哈", 1000, "男")); ???????userList.add(new User(2, "呵呵", 2000, "男")); ???????userList.add(new User(3, "嘻嘻", 3000, "女")); ???????userList.add(new User(4, "笨笨", 4000, "男")); ???????userList.add(new User(5, "聪聪", 5000, "男")); ???????userList.add(new User(6, "月月", 6000, "女")); ???????userList.add(new User(7, "花花", 7000, "女")); ???????Map<String, Object> map = new LinkedHashMap<String, Object>(); ???????map.put("total", userList.size()); ???????map.put("rows", userList); ???????JSONArray jsonArray = JSONArray.fromObject(map); ???????String jsonJAVA = jsonArray.toString(); ???????jsonJAVA = jsonJAVA.substring(1, jsonJAVA.length() - 1); ???????//以流的方式将JSON文本输出到DateGrid组件中 ???????response.setContentType("text/html;charset=UTF-8"); ???????PrintWriter pw = response.getWriter(); ???????pw.write(jsonJAVA); ???????pw.flush(); ???????pw.close(); ???}}

用Servlet返回JSON文本动态创建DataGrid

原文地址:https://www.cnblogs.com/loaderman/p/10059875.html

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