解析前端传递的JSON数据中可能如下
{ "result": "<input value="Test" type="button" onclick="alert(""OK"");" />", "msg": "test"}
此时去解析是无法解析出来的，存在 / 空格 多的双引号，
参考多个结果
针对双引号（利用中文双引号代替多余的英文双引号后去解析JSON串）
public String jsonStringConvert(String s) { ???????char[] temp = s.toCharArray(); ???????int n = temp.length; ???????for (int i = 0; i < n; i++) { ???????????if (temp[i] == ‘:‘ && temp[i + 1] == ‘"‘) { ???????????????for (int j = i + 2; j < n; j++) { ???????????????????if (temp[j] == ‘"‘) { ???????????????????????if (temp[j + 1] != ‘,‘ && temp[j + 1] != ‘}‘) { ???????????????????????????temp[j] = ‘”‘; ???????????????????????} else if (temp[j + 1] == ‘,‘ || temp[j + 1] == ‘}‘) { ???????????????????????????break; ???????????????????????} ???????????????????} ???????????????} ???????????} ???????} ???????return new String(temp); ???}针对空格（先调用此方法）
public String replaceBlank(String str) { ???????String dest = ""; ???????if (str != null) { ???????????Pattern p = Pattern.compile("\\s*|\t|\r|\n"); ???????????Matcher m = p.matcher(str); ???????????dest = m.replaceAll(""); ???????????// Pattern p2 = Pattern.compile("\\s*\""); ???????????// Matcher m2 = p2.matcher(dest); ???????????// dest = m2.replaceAll("\‘"); ???????????dest = dest.replace("=\"", "=‘"); ???????????p = Pattern.compile("\"\0*>"); ???????????m = p.matcher(dest); ???????????dest = m.replaceAll(">‘"); ???????} ???????return dest; ???}以上会造成数据的格式少了空格，需要自己去添加上（不能很好的解决问题）
对双引号进行转译
对富文本加密，后台解密存储
参考：https://blog.csdn.net/jbb0403/article/details/45918693
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JSON解析值富文本
原文地址：https://www.cnblogs.com/oldzhang1222/p/9953738.html