$.ajax 常用的套路

(function(){ ???window.webApi = new Object(); ???webApi.get = function(url,data,callback){ ???????$.ajax({ ???????????type:‘GET‘, ???????????data: data, ???????????url: url, ???????????success: function(result){ ???????????????callback && callback(result) ???????????} ???????}) ???}; ???webApi.formPost = function(url,data,callback){ ???????$.ajax({ ???????????type:‘POST‘, ???????????data: data, ???????????contentType:‘application/x-www-form-urlencoded‘, ???????????url: url, ???????????success: function(result){ ???????????????callback && callback(result) ???????????} ???????}) ???}; ???webApi.jsonPost = function(url,data,callback){ ???????$.ajax({ ???????????type:‘POST‘, ???????????data: JSON.stringify(data), ???????????contentType:‘application/json‘, ???????????url: url, ???????????success: function(result){ ???????????????callback && callback(result) ???????????} ???????}) ???}; ???window.getRequest = function(){ ???????var httpUrl = location.href; //获取url中‘?‘符后的字串 ???????var url = ‘?‘ + httpUrl.split(‘?‘)[1]; ???????var theRequest = {}; ???????if (url.indexOf(‘?‘) != -1) { ???????????var str = url.substr(1); ???????????var strs = str.split(‘&‘); ???????????for (var i = 0; i < strs.length; i++) { ???????????????theRequest[strs[i].split(‘=‘)[0]] = decodeURIComponent(strs[i].split(‘=‘)[1]); ???????????} ???????} ???????return theRequest; ???}})()