分享web开发知识

注册/登录|最近发布|今日推荐

主页 IT知识网页技术软件开发前端开发代码编程运营维护技术分享教程案例
当前位置:首页 > 代码编程

sprngmvc+restFul 请求报错:404

发布时间:2023-09-06 02:03责任编辑:蔡小小关键词:暂无标签

服务端代码

control类

 1 ????@RequestMapping(value="getUser",method = RequestMethod.POST) 2 ????@ResponseBody 3 ????public User getUser(HttpServletRequest request){ 4 ????????String name = request.getParameter("name"); 5 ????????String age = request.getParameter("age"); 6 ????????User user = new User(); 7 ????????user.setPassWord("123123"); 8 ????????user.setUserName("asdasd"); 9 ????????return user;10 ????}
View Code

spring核心控制器

 1 ????<!--配置Springmvc核心控制器 --> 2 ????<servlet> 3 ????????<servlet-name>springmvc</servlet-name> 4 ????????<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 5 ????????<init-param> 6 ????????????<param-name>contextConfigLocation</param-name> 7 ????????????<param-value>classpath:springMVC.xml</param-value> 8 ????????</init-param> 9 ????</servlet>10 ????<servlet-mapping>11 ????????<servlet-name>springmvc</servlet-name>12 ????????<url-pattern>*.action</url-pattern>13 ????</servlet-mapping>
View Code

客户端代码

 1 import com.alibaba.fastjson.JSONObject; 2 import org.apache.http.HttpResponse; 3 import org.apache.http.client.ClientProtocolException; 4 import org.apache.http.client.methods.HttpPost; 5 import org.apache.http.entity.StringEntity; 6 import org.apache.http.impl.client.DefaultHttpClient; 7 import org.apache.http.util.EntityUtils; 8 import org.junit.Test; 9 10 import java.io.IOException;11 12 public class HttpclientTest {13 ????@Test14 ????public void httpReqUrl()15 ????????????throws ClientProtocolException, IOException {16 ????????String url = "http://localhost:8080/ssm/user/getUser";17 ????????JSONObject json = new JSONObject();18 ????????DefaultHttpClient httpClient = new DefaultHttpClient();19 ????????HttpPost method = new HttpPost(url);20 ????????// 接收参数json列表21 ????????JSONObject jsonParam = new JSONObject();22 23 ????????StringEntity entity = new StringEntity(jsonParam.toString(), "utf-8");//解决中文乱码问题24 ????????entity.setContentEncoding("UTF-8");25 ????????entity.setContentType("application/json");26 ????????method.setEntity(entity);27 28 ????????HttpResponse result = httpClient.execute(method);29 ????????// 请求结束,返回结果30 ????????String resData = EntityUtils.toString(result.getEntity());31 ????????JSONObject resJson = json.parseObject(resData);32 ????????System.out.printf(":::"+resJson.toString());33 ????}34 }
View Code

 调用报错:http.404

报错原因:服务端配置的核心控制器,只拦截以 “.action”结尾的请求

解决方案:将服务端核心控制器配置“<url-pattern>*.action</url-pattern>”改为“<url-pattern>/</url-pattern>”

sprngmvc+restFul 请求报错:404

原文地址:https://www.cnblogs.com/malefeng/p/9290149.html

知识推荐

我的编程学习网——分享web前端后端开发技术知识。 垃圾信息处理邮箱 tousu563@163.com 网站地图
icp备案号 闽ICP备2023006418号-8 不良信息举报平台 互联网安全管理备案 Copyright 2023 www.wodecom.cn All Rights Reserved