如
urlpatterns = [
???url(r‘^Xadmin/‘,([
url(r‘^add/$‘, views.add)
url(r‘^delete/$‘, views.delete)
], None,None)),
这样就完成了一级分发
然后进行自行设计url
需求 3张表，增删改查, 12个url
如
127.0.0.1:8000/Xadmin/app01/add/
127.0.0.1:8000/Xadmin/app01/delete/
在urls.py编辑
def list_view(request):
???return HttpResponse(‘userindex‘)
def add_view(request):
???return HttpResponse(‘user_add‘)
def change_view(request, id):
???return HttpResponse(‘user_change‘)
def delete_view(request, id):
???return HttpResponse(‘user_delete‘)
def has_urls():
???temp = []
???temp.append(url(r‘^$‘,list_view))
???temp.append(url(r‘^add/$‘,add_view))
???temp.append(url(r‘^(\d+)/change/$‘,change_view))
???temp.append(url(r‘^(\d+)/delete/$‘,delete_view))
???print(temp)
???return temp
def get_urls():
???print(admin.site._registry)
???temp = []
???for model,admin_class_obj in admin.site._registry.items():
???????app_name = model._meta.app_label
???????model_name = model._meta.model_name
???????print(app_name,model_name)
???????temp.append(url(r‘^{0}/{1}/‘.format(app_name,model_name),(has_urls(), None,None)),)
???return temp
urlpatterns = [
???path(‘admin/‘, admin.site.urls),
???url(r‘^Xadmin/‘,(get_urls(), None,None)),]
settings.py
设置
INSTALLED_APPS = [
‘app01.apps.App01Config‘,
‘app02.apps.App02Config‘,
]
app01项目下的admin.py
from django.contrib import admin
from app01 import models
# Register your models here.
admin.site.register(models.Book)
admin.site.register(models.Publish)
app01项目下的models.py
app02项目下的admin.py
from django.contrib import admin
from app02 import models
# Register your models here.
admin.site.register(models.Order)
app01项目下的models.py
from django.db import models
class Order(models.Model):
???title = models.CharField(max_length=32)
???def __str__(self):
???????return self.title
设计url 通过分发的方式 ?Xadmin_demo
原文地址：https://www.cnblogs.com/Liang-jc/p/9568627.html