分享web开发知识

注册/登录|最近发布|今日推荐

主页 IT知识网页技术软件开发前端开发代码编程运营维护技术分享教程案例
当前位置:首页 > 教程案例

递归实现tree JQuery

发布时间:2023-09-06 02:11责任编辑:熊小新关键词:递归
<!DOCTYPE html><html xmlns="http://www.w3.org/1999/xhtml"><head> ???<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> ???<title></title> ???<script src="jquery-1.8.3.min.js"></script></head><body> ????<script type="text/javascript"> ???????$(function () { ???????????var data = [ ???????????{ id: 1, name: "办公管理", pid: 0 }, ???????????{ id: 2, name: "请假申请", pid: 1 }, ???????????{ id: 3, name: "出差申请", pid: 1 }, ???????????{ id: 4, name: "请假记录", pid: 2 }, ???????????{ id: 5, name: "系统设置", pid: 0 }, ???????????{ id: 6, name: "权限管理", pid: 5 }, ???????????{ id: 7, name: "用户角色", pid: 6 }, ???????????{ id: 8, name: "菜单设置", pid: 6 }, ???????????]; ???????????GetData(0, data); ???????????$("body").append(menus); ???????}); ????????//菜单列表html ???????var menus = ‘‘; ????????//根据菜单主键id生成菜单列表html ???????//id:菜单主键id ???????//arry:菜单数组信息 ???????function GetData(id, arry) { ???????????var childArry = GetParentArry(id, arry); ???????????if (childArry.length > 0) { ???????????????menus += ‘<ul>‘; ???????????????for (var i in childArry) { ???????????????????menus += ‘<li>‘ + childArry[i].name; ???????????????????GetData(childArry[i].id, arry); ???????????????????menus += ‘</li>‘; ???????????????} ???????????????menus += ‘</ul>‘; ???????????} ???????} ????????//根据菜单主键id获取下级菜单 ???????//id:菜单主键id ???????//arry:菜单数组信息 ???????function GetParentArry(id, arry) { ???????????var newArry = new Array(); ???????????for (var i in arry) { ???????????????if (arry[i].pid == id) ???????????????????newArry.push(arry[i]); ???????????} ???????????return newArry; ???????} ???</script></body></html>

  

递归实现tree JQuery

原文地址:https://www.cnblogs.com/macT/p/9525327.html

知识推荐

我的编程学习网——分享web前端后端开发技术知识。 垃圾信息处理邮箱 tousu563@163.com 网站地图
icp备案号 闽ICP备2023006418号-8 不良信息举报平台 互联网安全管理备案 Copyright 2023 www.wodecom.cn All Rights Reserved