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http请求

发布时间:2023-09-06 01:54责任编辑:苏小强关键词:http

一、接受请求的http数据

  1、接受客户请求的数据,例如xml数据格式,代码如下:

public String analyzeWeixinXMLStr(HttpServletRequest request){ ???????String ?xmlStr = null; ???????try ???????{ ???????????BufferedReader reader = request.getReader(); ???????????String temp = null; ???????????StringBuffer requestXml = new StringBuffer(); ???????????while((temp = reader.readLine()) != null) ???????????{ ???????????????requestXml.append(temp); ???????????} ???????????//System.out.println(requestXml.toString()); ???????????if(requestXml.toString().length()>0){ ???????????????// 转码,解决乱码的问题 ???????????????xmlStr = new String(requestXml.toString().getBytes("iso8859-1"), "UTF-8"); ???????????} ???????} ???????catch (Exception e) ???????{ ???????????xmlStr = null; ???????????OttExecutionContext.error(e,"WxCommBiz.analyzeWeixinXMLStr is error"); ???????} ???????return xmlStr; ???}

  2、将xml的数据格式转换为map,便于获取,代码如下:

public HashMap<String, String> analyzeWeixinXMLHashMap(String requestXml){ ???????HashMap<String, String> paramsXmlMap = null; ???????try ???????{ ???????????if(requestXml.toString().length()>0){ ???????????????paramsXmlMap = new HashMap<String, String>(); ???????????????//将请求写文件 ???????????????new TxtFileUtil().writeWeixMsgToFile("request", requestXml); ???????????????// 获取微信服务发送请求,并返回第一层级json格式数据 ???????????????Document document = DocumentHelper.parseText(requestXml); ???????????????Element items = document.getRootElement(); ???????????????for (Iterator i = items.elementIterator(); i.hasNext();) ???????????????{ ???????????????????Element item = (Element) i.next(); ???????????????????paramsXmlMap.put(item.getName(), item.getText()); ???????????????} ???????????} ???????} ???????catch (Exception e) ???????{ ???????????paramsXmlMap = null; ???????????OttExecutionContext.error(e,"WxCommBiz.analyzeWeixinXMLHashMap is error"); ???????} ???????return paramsXmlMap; ???}

   3、将xml格式的数据推送给接口服务器,并获取返回结果/*     * 将客服消息推送给新的呼叫中心     * @param reqXml 标准的微信公众平台的XML的消息结构内容     * @return

 ????* @throws Exception ????* @datetime 2017-05-10 ?????*/ ???public String pushMsg(String reqXml) throws Exception ???{ ???????String result=null; ???????try{
       //请求服务器接口(将数据推送给服务器接口) ???????????String address = SystemGlobals.getValue("addressCustomerService"); ???????????URL url = null; ???????????HttpURLConnection urlConn = null; ???????????url = new URL(address); ???????????urlConn = (HttpURLConnection) url.openConnection(); ???????????urlConn.setRequestMethod("POST"); ???????????urlConn.setDoOutput(true); ???????????OutputStream out = urlConn.getOutputStream(); ???????????//Post请求参数 ???????????reqXml=URLEncoder.encode(reqXml,"utf-8"); ???????????String param="msg="+reqXml; ???????????out.write(param.getBytes("utf-8")); ???????????out.flush(); ???????????out.close();       
       //接受服务器返回的数据结果
???????????StringBuffer str = new StringBuffer(); ????????????BufferedReader in = new BufferedReader(new InputStreamReader(urlConn.getInputStream(),"utf-8")); ????????????String inputLine = null; ????????????while ( (inputLine = in.readLine()) != null){ ????????????????str.append(inputLine); ????????????} ????????????in.close(); ????????????result=parseSingleStr(str.toString()); ???????????????????}catch(Exception e){ ???????????OttExecutionContext.error(e, "消息转发异常!"); ???????} ???????????????if(result!=null&&HTTP_SUCCESS.equals(result)){ ???????????OttExecutionContext.info("消息转发成功!result:"+result); ???????}else{ ???????????OttExecutionContext.info("消息转发失败!result:"+result); ???????} ???????????????return result; ???} ???private static final Pattern singleResPattern=Pattern.compile("(.+)\"http://tempuri.org/\">(\\S+)</(.+)"); ???/** ????* 解析xml格式单个返回结果 ????* @datetime 2017-4-12 ?????*/ ???public static String parseSingleStr(String resXML){ ???????if(resXML==null){ ???????????return null; ???????} ???????String result=null; ???????Matcher matcher=singleResPattern.matcher(resXML); ???????if(matcher.matches()){ ???????????MatchResult matchResult=matcher.toMatchResult(); ???????????result=matchResult.group(2); ???????} ???????return result; ???}

http请求

原文地址:https://www.cnblogs.com/ouyy/p/9034998.html

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