ssm框架下文件上传

1.页面上，通过input来准备file组件，该标签，必须给定name属性值同时，要求form表单必须给定一个属性：enctype="multipart/form-data"2.在pom.xml文件中，添加文件上传的第三方工具：commons-fileupload-1.3.2.jarcommons-io-2.2.jar3.在app-springmvc.xml配置文件中，准备上传操作的对象:CommonsMultipartResolver在这个对象中，我们可以对文件大小，编码方式等进行设定4.在控制器中，通过@RequestParam MultipartFile pic这种方式，来接收页面传递的文件这里，参数的名字必须与页面上file组件的name属性值一致此时，在控制器中，已经能够正常地接收页面上传的文件了，下一步，只需要把接收的这个文件，保存到服务器的硬盘上即可

<!-- 2文件上传依赖 --> ???????<dependency> ???????????<groupId>commons-fileupload</groupId> ???????????<artifactId>commons-fileupload</artifactId> ???????????<version>1.3.2</version> ???????</dependency>

<!-- 3文件上传 --><bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" > ????????<property name="maxUploadSizePerFile" value="102400000" ></property> ????</bean>

<!-- 4 控制器。。。文件上传 -->@RequestMapping(value="addFile",method=RequestMethod.POST) ???public String addFile(@RequestParam MultipartFile pic,HttpServletRequest request,Model model){ ???????String filename = pic.getOriginalFilename(); ???????System.out.println("接收到的文件的名字： "+filename); ???????String contentType = pic.getContentType(); ???????System.out.println("接收文件的类型： "+contentType); ???????InputStream iStream=null; ???????OutputStream oStream=null; ???????String realPath = request.getSession().getServletContext().getRealPath("/imgs"); ???????//得到一个随机的字符串 ???????String string = UUID.randomUUID().toString(); ???????String endname = filename.substring(filename.lastIndexOf("."), filename.length()); ???????????????/*try { ???????????is = pic.getInputStream(); ???????????os = new FileOutputStream(new File(realpath+"/"+uuid+endname)); ???????????//要把文件输出到硬盘上，第一种方式：自己写字节流 并通过边读边写操作完成输出 ???????????byte [] b = new byte[1024]; ???????????int len = is.read(b); ???????????while(len!=-1){ ???????????????os.write(b, 0, len); ???????????????len = is.read(b); ???????????} ???????????os.flush(); ???????????os.close(); ???????????is.close(); ???????} catch (IOException e) { ???????????e.printStackTrace(); ???????}*/ ???????????????????????//通过commons-io包提供的工具来完成拷贝 ???????try { ???????????iStream=pic.getInputStream(); ???????????oStream=new FileOutputStream(new File(realPath+"/"+string+endname)); ???????????FileCopyUtils.copy(iStream, oStream); ???????????oStream.flush(); ???????????oStream.close(); ???????????iStream.close(); ???????} catch (IOException e) { ???????????// TODO Auto-generated catch block ???????????e.printStackTrace(); ???????} ???????System.out.println("文件保存路径："+realPath+"/"+string+endname+"...."); ???????return "index"; ???}