{"dingtalk_corp_role_list_response":{"result":{"has_more":"false","list":{"role_groups":[{"group_name":"默认","roles":{"roles":[{"id":278146611,"role_name":"主管理员"},{"id":278146612,"role_name":"子管理员"},{"id":278146613,"role_name":"负责人"},{"id":278146614,"role_name":"主管"}]}},{"group_name":"职务","roles":{"roles":[{"id":278146616,"role_name":"财务"},{"id":278146617,"role_name":"人事"},{"id":278146618,"role_name":"出纳"},{"id":278146619,"role_name":"销售"},{"id":278146620,"role_name":"客服"},{"id":278146621,"role_name":"质检"},{"id":278146622,"role_name":"研发"},{"id":278146623,"role_name":"行政"},{"id":278146624,"role_name":"设计"},{"id":278146625,"role_name":"产品"},{"id":278554778,"role_name":"采购"}]}},{"group_name":"岗位","roles":{"roles":[{"id":278146627,"role_name":"普通员工"},{"id":278146628,"role_name":"经理"},{"id":278146629,"role_name":"科长"},{"id":278146630,"role_name":"部长"},{"id":278146631,"role_name":"总监"},{"id":278146632,"role_name":"管理层"},{"id":278146633,"role_name":"高级管理者"},{"id":278146634,"role_name":"总经理"}]}}]}},"request_id":"7iythn3xigry"}}
调用接口返回的json如下
现在要得到的是roles的 role_name和id,具体方法如下，其实还是很简单的，只不过需要耐心点。
public static List<RoleGroup> getAllRoleList(String access_token,Long size,Long offsize) throws ApiException, OApiResultException{ ???????DingTalkClient client = new DefaultDingTalkClient("https://eco.taobao.com/router/rest"); ???????CorpRoleListRequest req = new CorpRoleListRequest(); ???????List<RoleGroup> list ?= new ArrayList<>(); ???????req.setSize(size);//分页大小 ???????req.setOffset(offsize);//分页偏移 ???????CorpRoleListResponse rsp = client.execute(req, access_token); ???????JSONObject response = JSON.parseObject(rsp.getBody()); ????????if (response.containsKey("dingtalk_corp_role_list_response")) { ???????????JSONObject j1 = response.getJSONObject("dingtalk_corp_role_list_response"); ???????????JSONObject j2 = j1.getJSONObject("result"); ???????????JSONObject j3 = j2.getJSONObject("list"); ???????????JSONArray j5 = j3.getJSONArray("role_groups"); ???????????for (int i = 0; i < j5.size(); i++) { ???????????????JSONObject j6 = j5.getJSONObject(i); ???????????????JSONObject j7 = j6.getJSONObject("roles"); ???????????????JSONArray j8 = j7.getJSONArray("roles"); ???????????????if(j8!=null){ ???????????????for(int n = 0; n < j8.size(); n++){ ???????????????????RoleGroup g = j8.getObject(n, RoleGroup.class); ???????????????????????list.add(g); ???????????????}} ???????????} ???????????return list; ???????} ???????else { ???????????throw new OApiResultException("Role"); ???????} ???}
package com.alibaba.dingtalk.openapi.demo.role;public class RoleGroup { ???private String id; ???private String role_name; ???public String getId() { ???????return id; ???} ???public void setId(String id) { ???????this.id = id; ???} ???public String getRole_name() { ???????return role_name; ???} ???public void setRole_name(String role_name) { ???????this.role_name = role_name; ???}}对复杂json进行处理
原文地址：https://www.cnblogs.com/chenyangwang/p/8279050.html